(Easy)合并两个有序链表
将两个有序链表合并为一个新的有序链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。 

示例:

输入:1->2->4, 1->3->4
输出:1->1->2->3->4->4

自己题解:

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
class Solution {
    public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
        ListNode head = new ListNode(0);
        ListNode merge = head;
        while(l1 != null || l2 != null) {
            if (l1 == null) {
                merge.next = l2;
                l2 = l2.next;
                merge = merge.next;
                continue;
            }

            if (l2 == null) {
                merge.next = l1;
                l1 = l1.next;
                merge = merge.next;
                continue;
            }

            if (l1.val <= l2.val) {
                merge.next = l1;
                l1 = l1.next;
            } else {
                merge.next = l2;
                l2 = l2.next;
            }

            merge = merge.next;
        }

        return head.next;
    }
}

分析: while的判断里栽了跟斗,判断错了,本来这题可以更快解出来的。